Given an array of integers, find the optimal partition point that minimizes the absolute difference in the total weight of gems delivered to each station.
Explanation: Step 1: Sort the array in descending order. [57, 41, 22, 13, 11, 9, 7, 5, 3, 1]. Step 2: Initialize two pointers, i and j, at the start and end of the array. i = 0, j = 9. Step 3: Initialize two variables, left_sum and right_sum, to 0. left_sum = 0, right_sum = 0. Step 4: Move the pointers towards each other, and at each step, add the current element to the left_sum or right_sum. Step 5: If the absolute difference between left_sum and right_sum is less than the current minimum difference, update the minimum difference and the optimal partition point. Step 6: Return the optimal partition point.
Explanation: Step 1: Sort the array in descending order. [100, 90, 80, 70, 60, 50, 40, 30, 20, 10]. Step 2: Initialize two pointers, i and j, at the start and end of the array. i = 0, j = 9. Step 3: Initialize two variables, left_sum and right_sum, to 0. left_sum = 0, right_sum = 0. Step 4: Move the pointers towards each other, and at each step, add the current element to the left_sum or right_sum. Step 5: If the absolute difference between left_sum and right_sum is less than the current minimum difference, update the minimum difference and the optimal partition point. Step 6: Return the optimal partition point.
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