Subarray Product Validator Solution

Explanation: Step-by-step: Given the array [10, 5, 3, 7, 9] and K=10, we iterate through the array using two pointers. We start with the first pointer at index 0 and the second pointer at index 1. The product of the subarray [10] is 10, which is not less than K. We move the second pointer to index 2. The product of the subarray [10, 5] is 50, which is not less than K. We move the second pointer to index 3. The product of the subarray [10, 5, 3] is 150, which is not less than K. We move the second pointer to index 4. The product of the subarray [10, 5, 3, 7] is 210, which is not less than K. We move the second pointer to index 5. The product of the subarray [10, 5, 3, 7, 9] is 1890, which is not less than K. We reset the second pointer to index 1 and move it to index 2. The product of the subarray [5] is 5, which is less than K. We reset the second pointer to index 1 and move it to index 3. The product of the subarray [5, 3] is 15, which is less than K. We reset the second pointer to index 1 and move it to index 4. The product of the subarray [5, 3, 7] is 105, which is less than K. We reset the second pointer to index 1 and move it to index 5. The product of the subarray [5, 3, 7, 9] is 945, which is not less than K. We reset the second pointer to index 1 and move it to index 2. The product of the subarray [3] is 3, which is less than K. We reset the second pointer to index 1 and move it to index 3. The product of the subarray [3, 7] is 21, which is less than K. We reset the second pointer to index 1 and move it to index 4. The product of the subarray [3, 7, 9] is 189, which is not less than K. We reset the second pointer to index 1 and move it to index 2. The product of the subarray [7] is 7, which is less than K. We reset the second pointer to index 1 and move it to index 3. The product of the subarray [7, 9] is 63, which is not less than K. We reset the second pointer to index 1 and move it to index 2. The product of the subarray [9] is 9, which is less than K. We count the subarrays [5], [3], [7], and [9] and return 4.

Explanation: Step-by-step: Given the array [1, 2, 3, 4, 5, 6, 7, 8, 9] and K=10, we iterate through the array using two pointers. We start with the first pointer at index 0 and the second pointer at index 1. The product of the subarray [1] is 1, which is less than K. We move the second pointer to index 2. The product of the subarray [1, 2] is 2, which is less than K. We move the second pointer to index 3. The product of the subarray [1, 2, 3] is 6, which is less than K. We move the second pointer to index 4. The product of the subarray [1, 2, 3, 4] is 24, which is not less than K. We reset the second pointer to index 1 and move it to index 2. The product of the subarray [2] is 2, which is less than K. We reset the second pointer to index 1 and move it to index 3. The product of the subarray [2, 3] is 6, which is less than K. We reset the second pointer to index 1 and move it to index 4. The product of the subarray [2, 3, 4] is 24, which is not less than K. We reset the second pointer to index 1 and move it to index 2. The product of the subarray [3] is 3, which is less than K. We reset the second pointer to index 1 and move it to index 3. The product of the subarray [3, 4] is 12, which is not less than K. We reset the second pointer to index 1 and move it to index 2. The product of the subarray [4] is 4, which is less than K. We reset the second pointer to index 1 and move it to index 3. The product of the subarray [4, 5] is 20, which is not less than K. We reset the second pointer to index 1 and move it to index 2. The product of the subarray [5] is 5, which is less than K. We reset the second pointer to index 1 and move it to index 3. The product of the subarray [5, 6] is 30, which is not less than K. We reset the second pointer to index 1 and move it to index 2. The product of the subarray [6] is 6, which is less than K. We reset the second pointer to index 1 and move it to index 3. The product of the subarray [6, 7] is 42, which is not less than K. We reset the second pointer to index 1 and move it to index 2. The product of the subarray [7] is 7, which is less than K. We reset the second pointer to index 1 and move it to index 3. The product of the subarray [7, 8] is 56, which is not less than K. We reset the second pointer to index 1 and move it to index 2. The product of the subarray [8] is 8, which is less than K. We reset the second pointer to index 1 and move it to index 3. The product of the subarray [8, 9] is 72, which is not less than K. We reset the second pointer to index 1 and move it to index 2. The product of the subarray [9] is 9, which is less than K. We count the subarrays [1], [2], [3], [4], [5], [6], [7], [8], and [9] and return 9.