easyStringsPattern: Frequency Map
Rearrangement Equivalence Checker Solution
Problem Statement
Given two strings `s` and `t`, determine if one can be rearranged to form the other. The strings are comprised of characters, and two strings are considered 'equivalent' if they contain the same characters with the same frequencies.
Examples
Example 1:
Input:["listen","silent"]
Output:true
Explanation: The two strings are anagrams of each other
Example 2:
Input:["hello","world"]
Output:false
Explanation: The two strings are not anagrams of each other
Constraints
- 1 <= s.length, t.length <= 5 * 10^4
- s and t consist of lowercase English letters.
Time: O(N) Space: O(1)
Use a hash table to count character frequencies in both codes with a time complexity of O(n)
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