Given a transmission message, find the frequency of each character and then reorder the message based on the frequency of characters in descending order. If two characters have the same frequency, the character with the smaller ASCII value will come first.
Explanation: Step-by-step: First, we count the frequency of each character in the input string 'abcabc'. The frequency of 'a' is 3, 'b' is 2, and 'c' is 2. Then, we sort the characters based on their frequency in descending order and ASCII value in ascending order. Since 'a' has a higher frequency than 'b' and 'c', it comes first. Among 'b' and 'c', 'b' has a smaller ASCII value, so it comes before 'c'. Therefore, the sorted string is 'acbabcc'.
Explanation: Step-by-step: First, we count the frequency of each character in the input string 'zzzww'. The frequency of 'z' is 3, 'w' is 1. Then, we sort the characters based on their frequency in descending order and ASCII value in ascending order. Since 'z' has a higher frequency than 'w', it comes first. Therefore, the sorted string is 'zzzww'.
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