Optimizing Warehouse Storage 2 Solution

Explanation: We initialize the maximum sum and the current sum to the first element of the prefix. Then, we iterate through the rest of the prefix, updating the current sum by adding each element and resetting it if it becomes negative. The maximum sum is updated whenever the current sum exceeds it. Finally, we return the maximum sum, which is 20 in this case.

Explanation: We initialize the maximum sum and the current sum to the first element of the prefix. Then, we iterate through the rest of the prefix, updating the current sum by adding each element and resetting it if it becomes negative. The maximum sum is updated whenever the current sum exceeds it. Finally, we return the maximum sum, which is 7 in this case.