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Maximum Trade Value Optimization Solution

Problem Statement

Given an array of integers tradeValues representing the trade values of space stations, determine the maximum total trade value that can be achieved by either keeping the trade value of a station as is or replacing it with the difference between the total trade values of all previous stations and all subsequent stations.

Example 1
Input
[10, 20, 30, 40, 50]
Output
250

Explanation: Step-by-step: Calculate prefix sum as [10, 30, 60, 100, 150] and suffix sum as [50, 80, 110, 140, 170]. Replace 20 with 30-170=-140, 30 with 60-140=-80, 40 with 100-110=-10, 50 with 150-100=50. The maximum total trade value is 10 + (-140) + (-80) + (-10) + 50 = 250.

Example 2
Input
[1, 2, 3, 4, 5]
Output
15

Explanation: Step-by-step: Calculate prefix sum as [1, 3, 6, 10, 15] and suffix sum as [5, 7, 9, 11, 13]. Replace 2 with 3-13=-10, 3 with 6-9=-3, 4 with 10-11=-1. The maximum total trade value is 1 + (-10) + (-3) + (-1) + 5 = 15.

Constraints

  • 1 <= number of space stations <= 1000
  • -10000 <= trade value of each station <= 10000
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Maximum Trade Value Optimization — Problem Statement & Solution Guide

ArraysMediumMixed
TimeO(n)
|
SpaceO(1)

Problem Description

Given an array of integers tradeValues representing the trade values of space stations, determine the maximum total trade value that can be achieved by either keeping the trade value of a station as is or replacing it with the difference between the total trade values of all previous stations and all subsequent stations.

Examples

Example 1

Input

[10, 20, 30, 40, 50]

Output

250

Explanation: Step-by-step: Calculate prefix sum as [10, 30, 60, 100, 150] and suffix sum as [50, 80, 110, 140, 170]. Replace 20 with 30-170=-140, 30 with 60-140=-80, 40 with 100-110=-10, 50 with 150-100=50. The maximum total trade value is 10 + (-140) + (-80) + (-10) + 50 = 250.

Example 2

Input

[1, 2, 3, 4, 5]

Output

15

Explanation: Step-by-step: Calculate prefix sum as [1, 3, 6, 10, 15] and suffix sum as [5, 7, 9, 11, 13]. Replace 2 with 3-13=-10, 3 with 6-9=-3, 4 with 10-11=-1. The maximum total trade value is 1 + (-10) + (-3) + (-1) + 5 = 15.

Constraints

  • 1 <= number of space stations <= 1000
  • -10000 <= trade value of each station <= 10000

Optimal Approach & Strategy

The optimal approach involves using dynamic programming to store the maximum total trade values for subproblems and applying a greedy strategy to choose the maximum trade value at each station. This approach would have a significant improvement in efficiency and scalability.

Brute Force Approach

A naive approach would involve iterating over the list of trade values and recalculating the total trade values of all previous and subsequent stations for each station, resulting in a time complexity of O(n²). This approach would be inefficient for large inputs. The brute-force solution would also require checking all possible combinations of keeping or replacing trade values.

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