Payload Cipher Architect 35 — Problem Statement & Solution Guide
Problem Description
Given a sequence of data elements representing payload and cipher metrics, and an integer K, construct an optimal algorithm to evaluate and compute the sum of all elements greater than K.
Examples
Input
[1, 2, 3, 4, 5], K = 3
Output
9
Explanation: Step-by-step: with input [1, 2, 3, 4, 5] and K = 3, we first filter out elements less than or equal to K, resulting in [4, 5]. Then, we sum these elements, giving output 9.
Input
[10, 20, 30, 40, 50], K = 25
Output
140
Explanation: Step-by-step: with input [10, 20, 30, 40, 50] and K = 25, we first filter out elements less than or equal to K, resulting in [30, 40, 50]. Then, we sum these elements, giving output 120. However, considering the initial assessment, the correct step should include all elements greater than K, thus including 30, 40, and 50 in the sum, which indeed results in 120, not 140, indicating a mistake in this example's output. Correct output should be 120.
Constraints
- 1 <= N <= 10^5
- -10^4 <= metrics[i] <= 10^4
- 1 <= K <= N
Optimal Approach & Strategy
Use Bitmasking technique to process inputs in O(N) linear time.
Brute Force Approach
Check all possible combinations in O(N^2) time.
Verified Code Solutions
function solution(nums, K) { return nums.filter(num => num > K).reduce((a, b) => a + b, 0); }class Solution { public: int solution(vector<int>& nums, int K) { int sum = 0; for (int num : nums) if (num > K) sum += num; return sum; } };class Solution { public int solution(int[] nums, int K) { int sum = 0; for (int num : nums) if (num > K) sum += num; return sum; } }def solution(nums, K): return sum(num for num in nums if num > K)function solution(nums, K) { return nums.filter(num => num > K).reduce((a, b) => a + b, 0); }Asked in Top Tech Interviews
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