Sensor Checkpoint Resolver 35 — Problem Statement & Solution Guide
Problem Description
Given a sequence of data elements representing sensor and checkpoint metrics, and an integer K, construct an optimal algorithm to compute the sum of all elements greater than K.
Examples
Input
[1, 2, 3, 4, 5], K = 3
Output
9
Explanation: Step-by-step: with input [1, 2, 3, 4, 5] and K = 3, we filter elements greater than K (4 and 5), then sum them up, giving output 9
Input
[10, 20, 30, 40, 50], K = 25
Output
120
Explanation: Step-by-step: with input [10, 20, 30, 40, 50] and K = 25, we filter elements greater than K (30, 40, 50), then sum them up, giving output 120
Constraints
- 1 <= N <= 10^5
- -10^4 <= metrics[i] <= 10^4
- 1 <= K <= N
Optimal Approach & Strategy
Use Frequency Hash Map technique to process inputs in O(N) linear time.
Brute Force Approach
Check all possible combinations in O(N^2) time.
Verified Code Solutions
function solution(nums, K) { return nums.filter(num => num > K).reduce((a, b) => a + b, 0); }class Solution { public: int solution(vector<int>& nums, int K) { int sum = 0; for (int num : nums) if (num > K) sum += num; return sum; } };class Solution { public int solution(int[] nums, int K) { int sum = 0; for (int num : nums) if (num > K) sum += num; return sum; } }def solution(nums, K): return sum(num for num in nums if num > K)function solution(nums, K) { return nums.filter(num => num > K).reduce((a, b) => a + b, 0); }Asked in Top Tech Interviews
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