Given a singly linked list, find the value stored in the middle node. If the linked list contains an even number of nodes, return the value of the second middle node. You must implement this by traversing the list only once using the fast and slow pointer technique.
Explanation: The list has 5 nodes, so the middle node is 3.
Explanation: The list has 4 nodes. The middle nodes are 20 and 30; the second middle node is 30.
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