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Tome Signal Synthesizer 37 Solution

Problem Statement

Given a sequence of data elements representing tome and signal metrics, construct an optimal algorithm to evaluate and compute the target synthesizer value under given operational constraints.

Example 1
Input
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 5
Output
40

Explanation: Step-by-step: Given the input array [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] and the target value 5, we first find the index of the first element greater than 5, which is 5. Then we sum up all elements from index 5 to the end of the array, which are 6, 7, 8, 9, 10. The sum is 6 + 7 + 8 + 9 + 10 = 40.

Example 2
Input
[10, 20, 30, 40, 50], 25
Output
0

Explanation: Step-by-step: Given the input array [10, 20, 30, 40, 50] and the target value 25, we first find the index of the first element greater than 25, which does not exist. Therefore, the sum of elements greater than 25 is 0.

Constraints

  • 1 <= N <= 10^5
  • -10^4 <= metrics[i] <= 10^4
  • 1 <= K <= N
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Tome Signal Synthesizer 37 — Problem Statement & Solution Guide

Binary SearchMediumBitmasking
TimeO(n log n)
|
SpaceO(n)

Problem Description

Given a sequence of data elements representing tome and signal metrics, construct an optimal algorithm to evaluate and compute the target synthesizer value under given operational constraints.

Examples

Example 1

Input

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 5

Output

40

Explanation: Step-by-step: Given the input array [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] and the target value 5, we first find the index of the first element greater than 5, which is 5. Then we sum up all elements from index 5 to the end of the array, which are 6, 7, 8, 9, 10. The sum is 6 + 7 + 8 + 9 + 10 = 40.

Example 2

Input

[10, 20, 30, 40, 50], 25

Output

0

Explanation: Step-by-step: Given the input array [10, 20, 30, 40, 50] and the target value 25, we first find the index of the first element greater than 25, which does not exist. Therefore, the sum of elements greater than 25 is 0.

Constraints

  • 1 <= N <= 10^5
  • -10^4 <= metrics[i] <= 10^4
  • 1 <= K <= N

Optimal Approach & Strategy

Use Bitmasking technique to process inputs in O(N) linear time.

Brute Force Approach

Check all possible combinations in O(N^2) time.

Verified Code Solutions

JavaScript Solution
Time: O(n log n)
function solution(nums, k) {
   let sum = 0;
   for (let i = 0; i < nums.length; i++) {
       if (nums[i] > k) {
           sum += nums[i];
       } else {
           break;
       }
   }
   return sum;
}

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